#include <stdio.h>

void out(int *a, int arr[], char *str, int sz){
    printf("%d\n",*a);
    //in C, when you pass an array to a function, it decays into a pointer, and you lose the information
    //about its size. In this case, you won't be able to calculate the size of the array inside the 
    //function accurately without passing it explicitly
    
    //size_t sz = sizeof(arr)/sizeof(arr[0]);
    
    for(int i=0;i<sz;i++){
        printf("%d",arr[i]);
    }
    printf("\n%s",str);
}

int main() {
    int a = 10;
    int arr[10] = {1,2,3,4,5,6};
    char *str = "adarsh";

    size_t sz = sizeof(arr)/sizeof(arr[0]);

    out(&a,arr,str,sz);
    return 0;
}