#include <stdio.h>
int main() 
{
    double x;
    int n;
    scanf("%lf", &x);
    printf("Enter the value of x:%lf \n",x); 
    
    scanf("%d", &n);
    printf("Enter the number of terms (n):%d \n",n);
   
    
    double result = 1.0;
    double term = 1.0;

    for (int i = 1; i <= n; i++) 
    {
        term = x / i; //term=term(x/i)
        result += term;
    }

    printf("e^%.2lf is approximately %.6lf\n", x, result);

    return 0;
}