//C program to demonstrate scrunity of
// 2 Common Array elements Using Brute force
#include <stdio.h>

int main() 
{
    int array1[]={8,2,3,4,5,6,7,1};
    int array2[]={4,5,7,11,6,1};
    int i,j,flag,x,k=0;
    int result[100];
    printf("Common elements are: ");

    //To traverse in array1
    for(i=0;i<sizeof(array1)/4;i++){

        //To traverse in array2
        for(j=0;j<sizeof(array2) /4;j++){

            //To match the elements of array1 with elements of
            //array2
            if(array1[i]==array2[j]){

                flag=0;

                //To traverse in result array
                for(x=0;x<k;x++){

                    //Check whether found element is 
                    //already  present in result array or
                    //not
                    if(result[x] == array1[i]){
                        flag++;
                    }
                }

                //If we found a new element which is common
                //in both arrays then store it in result
                //array and print it
                if(flag==0){

                    result[k]=array1[i];
                    printf("%d ",result[k]);
                    k++;
                }
            }
        }
    }
}

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