It is the smallest number expressible as a sum of two cubes in two different ways.
# Function to check if a number can be expressed as the sum of two cubes in two different ways
def is_special_number(n):
    # Dictionary to store sums of cubes
    cube_sums = {}
    
    # Iterate through possible pairs of numbers
    for a in range(1, int(n ** (1/3)) + 1):
        for b in range(a, int(n ** (1/3)) + 1):
            cube_sum = a**3 + b**3
            if cube_sum in cube_sums:
                cube_sums[cube_sum].append((a, b))
            else:
                cube_sums[cube_sum] = [(a, b)]
    
    # Check for the number of ways to express n as the sum of two cubes
    if n in cube_sums and len(cube_sums[n]) > 1:
        return cube_sums[n]
    else:
        return None

# Test the function with the number 1729
number = 1729
result = is_special_number(number)

if result:
    print(f"The number {number} can be expressed as the sum of two cubes in two different ways:")
    for pair in result:
        print(f"{number} = {pair[0]}^3 + {pair[1]}^3")
else:
    print(f"The number {number} cannot be expressed as the sum of two cubes in two different ways.")