Write the in_order() function, which has a list of integers as a parameter,
#and returns True if the integers are sorted in descending order (in order from high to low) or False otherwise. 
#The program outputs "In descending order" if the list is sorted, or "Not in order" if the list is not sorted.

#Ex: If the list passed to the in_order() function is [5, 6, 7, 8, 3], then the function returns False and the program outputs:

#Not in order
#Ex: If the list passed to the in_order() function is [10, 8, 7, 6, 5], then the function returns True and the program outputs:

#In descending order
#Note: Use a for loop. DO NOT use sorted() or sort().


def in_order(nums):
    # Type your code here.
    for i in range(len(nums)-1): 
        if nums[i] < nums[ i + 1]:
            return False
        return True
        
if __name__ == '__main__':
    # Test out-of-order example
    nums1 = [5, 6, 7, 8, 3]
    if in_order(nums1):
        print('In descending order')
    else:
        print('Not in order')
        
    # Test in-order example
    nums2 = [10, 8, 7, 6, 5]
    if in_order(nums2):
        print('In descending order')
    else:
        print('Not in order')