//we have to print the following pattern for a given value "n"
/*
for n=3
 *** 
* * *
** **  
* * *
 *** 

for n=5
 ******* 
* ***** *
** *** **
*** * ***
**** ****
*** * ***
** *** **
* ***** *
 ******* 

*/

#include<bits/stdc++.h>
using namespace std;
int main(){
    int n;
    cin>>n;
    int m=(2*n)-1;
    for(int i=1;i<=m;i++){
        for(int j=1;j<=m;j++){
            if(i==j || i+j==2*n){
                cout<<" ";
            }
            else{
                cout<<"*";
            }
        }
        cout<<"\n";
    }
    return 0;
}