//C program for above approach

#include <iostream>
using namespace std;

/* Function to check if x is power of 2*/
bool isPowerOfTwo(int n)
{
    /* First x in the below expression is for the case when
    *x is 0 */
    int cnt=0;
    while(n>0){
        if((n & 1) == 1) {
            cnt++;
        }
        n= n>>1;//keep dividing by 2 using right  
                // shift operator
    }
    
    if(cnt==1){ //if cnt = 1 only then it is power of 2
        return true;
    }
    return false;
}

//Driver Code
int main() 
{
    //Function Call
    isPowerOfTwo(56) ? cout << "Yes\n" : cout<< "No\n";
    isPowerOfTwo(128) ? cout << "Yes\n" : cout<< "No\n";
    return 0;
}