#A year in the modern Gregorian Calendar consists of 365 days.
#In reality, the earth takes longer to rotate around the sun. 
#To account for the difference in time, every 4 years, a leap year takes place. 
#A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

#1) The year must be divisible by 4

#2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years

#Some example leap years are 1600, 1712, and 2016.

#Write a program that takes in a year and determines whether that year is a leap year.

is_leap_year = False 

input_year = int(input())

# if the uear is a centrury (1700, 1800) must be divisble by 400 

if input_year % 400 == 0: 
    print(f'{input_year} - leap year')

elif input_year % 100 == 0: 
    print(f'{input_year} - not a leap year')

elif input_year % 4 == 0: 
    print(f'{input_year} - leap year')

else: 
    print(f'{input_year} - not a leap year')