3-25-5

Jenday1230 · March 25, 2026

clc 
clear 

A = [ 5 0 2; -1 3 0]
B =[5 1 2; 0 3 0 ]

z1 = ~A
z2 = A & B 

z3 = A|B


a = 2 
b = 4 
c = 10 

d1 = a<b && b<c 
d2 = a<b && b>c 
d3 = a<b || b>c

Output

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